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2 years ago

15

ASAP!! Find the length of side x in simplest form with a rational denominator

1 answer:

lidiya [134]2 years ago

4 0

Answer:

$x=\sqrt{14}$

Step-by-step explanation:

This triangle is a 45-45-90 triangle.

By using the image I posted, we can find x easily.

So, we have $\sqrt{7}$ as one of the sides.

They hypotenuse, which is x is just $\sqrt{7} \sqrt{2}$

Simplify and we get x = $\sqrt{14}$

You might be interested in

Two more than 5 times a number is greater than or equal to 3

jenyasd209 [6]

Answer:

n ≥ 1/5

Step-by-step explanation:

Let the number be n. Then 5n + 2 ≥ 3.

If you want to solve this for n, then subtract 2 from both sides, obtaining:

5n ≥ 1. Isolate n by dividing both sides by 5. Then we have n ≥ 1/5

3 0

3 years ago

I need some help!!!!!!!!!!!!!!!!!!!!!!!

vampirchik [111]

Step-by-step explanation:

We are dealing with theoretical probability. This means that our probability of said outcome is

$\frac{x}{y}$

where x is the outcome we want, and y is the total number of outcomes possible.

28. There is 3 triangles out of 6 polygons so the probability is 1/2.

29.There is 1 Pentagon so the probability is 1/6.

30. This is a complement to question 28. A complement is the inverse of the problem. A complement and its original add to 1 so the probability of both getting a triangle is 1/2.

31. There is 4 non quadraletrial so the probability is 2/3.

32. There is 3 figures that has more sides than three so 1/2 is the probability.

33.There is only multi right angles figures so 1/2 is the probability.

34. There is 30 days in April so the probability it's the 29th is

$\frac{1}{30}$

35. There is 31 days in July and 15 days after the 16th. So the probability

is

$\frac{15}{31}$

3 0

2 years ago

1.Which equation gives the direct variation if y=8 when x=2?

Mama L [17]

First one is y=4x and the second one is y=2x

3 0

2 years ago

Approximately 4% of silicon wafers produced by a manufacturer have fewer than two large flaws. If Y, the number of flaws per waf

Doss [256]

Y ~ Po (λ)

P(Y < 2) = P(Y ≤ 1) = 0.04

Plug into the pdf for Po(λ), and solve for λ

After that, use your answer to find P(Y > 5)

6 0

2 years ago

There are three power plants [X, Y, Z] that at any given time each one either generates electricity or idles. Event A is that pl

insens350 [35]

We're told that

$P(A\cap B)=0.15$

$P(A\cup B)^C=0.06\implies P(A\cup B)=0.94$

$P(B\mid A)=P(B^C\mid A)=0.5$

where the last fact is due to the law of total probability:

$P(A)=P(A\cap B)+P(A\cap B^C)$

$\implies P(A)=P(B\mid A)P(A)+P(B^C\mid A)P(A)$

$\implies 1=P(B\mid A)+P(B^C\mid A)$

so that $B\mid A$ and $B^C\mid A$ are complementary.

By definition of conditional probability, we have

$P(B\mid A)=P(B^C\mid A)$

$\implies\dfrac{P(A\cap B)}{P(A)}=\dfrac{P(A\cap B^C)}{P(A)}$

$\implies P(A\cap B)=P(A\cap B^C)$

We make use of the addition rule and complementary probabilities to rewrite this as

$P(A\cap B)=P(A\cap B^C)$

$\implies P(A)+P(B)-P(A\cup B)=P(A)+P(B^C)-P(A\cup B^C)$

$\implies P(B)-[1-P(A\cup B)^C]=[1-P(B)]-P(A\cup B^C)$

$\implies2P(B)=2-[P(A\cup B)^C+P(A\cup B^C)]$

$\implies2P(B)=[1-P(A\cup B)^C]+[1-P(A\cup B^C)]$

$\implies2P(B)=P(A\cup B)+P(A\cup B^C)^C$

$\implies2P(B)=P(A\cup B)+P(A^C\cap B)\quad(*)$

By the law of total probability,

$P(B)=P(A\cap B)+P(A^C\cap B)$

$\implies P(A^C\cap B)=P(B)-P(A\cap B)$

and substituting this into $(*)$ gives

$2P(B)=P(A\cup B)+[P(B)-P(A\cap B)]$

$\implies P(B)=P(A\cup B)-P(A\cap B)$

$\implies P(B)=0.94-0.15=\boxed{0.79}$

8 0

2 years ago