Answer:
I THINK expose all six plants to green light
Explanation:
How do seed plants protect their embryos?
Reptilian embryos are protected from desiccation by a leathery shell. Similarly, sporophytes of both gymnosperms and angiosperms protect embryos within, and they also protect male gametophytes against desiccation using .....
Answer: 36.53g
Explanation:
First we need to find the amount of NaCl that dissolves in 1L of the solution that produced 5M of NaCl
Molarity = 5M
MM of NaCl = 58.45
Molarity = Mass conc (g/L) / MM
Mass conc. (g/L) of NaCl = Molarity x MM
= 5 x 58.45 = 292.25g
Next, we need to find the amount that will dissolve in 125mL(i.e 0.125L)
From the calculations above,
292.25g of NaCl dissolved in 1L
Therefore Xg of NaCl will dissolve in 0.125L of the solution i.e
Xg of NaCl = 292.25 x 0.125 = 36.53g.
Therefore 36.53g of NaCl will dissolve in 125mL of the solution
Ksp of copper(II) hydroxide Cu(OH)2 is 4.9 x 10-8.
Chemical reaction (dissociation) of copper(II) hydroxide in water:
Cu(OH)2(s) → Cu²⁺(aq) + 2OH⁻(aq).
Ksp(Cu(OH)2) = [Cu²⁺]·[OH⁻]².
[Cu²⁺] = 2.42 x 10-3 mol/l; solubility od copper ions
[OH⁻] = 2[Cu²⁺] = 2 x 2.42 x 10-3 mol/l
[OH⁻] = 4.48 x 10-3 mol/l; solubility of hydroxide ions
Ksp = 2.42 x 10-3 mol/l x (4.48 x 10-3 mol/l)²
Ksp = 4.9 x 10-8
Ksp is the solubility product constant for a solid substance dissolving in an aqueous solution.
Solubility of the compound depends on the temperature of the solution and the structure of that compound.
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