Point A is the midpoint of side XZ and point B is the
1 answer:
Answer:
Option (2)
Step-by-step explanation:
Given question is incomplete; here is the complete question.
Point A is the midpoint of side XZ and point B is the midpoint of side YZ.
Triangle XYZ is cut by line segment AB. Point A is the midpoint of side XZ and point B is the midpoint of side YZ. The length of XY is (5x - 7), the length of AB is (x + 1), and the lengths of XA and ZA are (2x - 2). The lengths of YB and BZ are congruent.
What is AX ?
2 units
4 units
6 units
8 units
From the figure attached,
XYZ is a triangle having A and B as the midpoints of the sides XZ and YZ.
By the theorem of midpoints,
AB =
Since AB = (x + 1) and XY = (5x - 7)
(x + 1) =
2x + 2 = 5x - 7
5x - 2x = 2 + 7
3x = 9
x = 3
Therefore, side AB = 3 + 1 = 4 units
Side XY = (5x - 7)
= 15 - 7
= 8 units
Side XA = 2(x - 1)
= 4 units
Therefore, Option (2) will be the answer.
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Answer:
1,809.98 lb*m/s^2
Step-by-step explanation:
First, we want to know how much weight of the boulder is projected along the path in which the boulder can move.
The weight of the boulder is:
W = 322lb*9.8 m/s^2 = (3,155.6 lb*m/s^2)
This weight has a direction that is vertical, pointing downwards.
Now, we know that the angle of the hill is 35°
The angle that makes the direction of the weight and this angle, is:
(90° - 35°)
(A rough sketch of this situation can be seen in the image below)
Then we need to project the weight over this direction, and that will be given by:
P = W*cos(90° - 35°) = (3,155.6 lb*m/s^2)*cos(55°) = 1,809.98 lb*m/s^2
This is the force that Samuel needs to exert on the boulder if he wants the boulder to not roll down.
