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3 years ago

Write an equation for the reaction of the Tollens reagent withheptanal?

Chemistry

1 answer:

dangina [55]3 years ago

8 0

Answer:

$CH_3 CH_2 CH_2 CH_2 CH_2 CH_2 CHO + 2[Ag(NH_3)_2]+ 3 H_2 O$ = $CH_3 CH_2 CH_2 CH_2 CH_2 CH_2 COOH +2Ag + 4NH_3$

Explanation:

Tollens test is carried out to perceive difference between aldehydes and ketones on the basis of their capability to oxidized easily.

when Tollens react with aldehyde (heptanal) , a silver mirror is form on inner side of container.

The reaction between tollens and heptanal is given as

$CH_3 CH_2 CH_2 CH_2 CH_2 CH_2 CHO + 2[Ag(NH_3)_2]+ 3 H_2 O$ = $CH_3 CH_2 CH_2 CH_2 CH_2 CH_2 COOH +2Ag + 4NH_3$

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$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:mass = 11.42 \:\: grams$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: Q = ms\Delta T$

$\textsf{Q = heat evolved/absorbed = 501 J}$

$\textsf{m = mass in gram = ?}$

$\textsf{s = specific heat = 0.45}$

$\textsf{ΔT = change in temp = 120 - 22.5 =97.5°C}$

$\large\textsf{Find m : }$

$\qquad \tt \rightarrow \: 501 = m \sdot(0.45) \sdot(97.5)$

$\qquad \tt \rightarrow \: 501 = m \sdot43.875$

$\qquad \tt \rightarrow \: m = \dfrac{501}{43.875}$

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