1 mole ------------- 6.02x10²³ atoms
4.93 moles ------- ??
4.93 x ( 6.02x10²³) / 1 =
=> 2.96x10²⁴ atoms
Metals of Group 1 donate 1 electron from its ns orbital to form ionic bond, where n is the no. of its outermost shell.
Metals of Group 2<span> donate 2 electrons from its ns orbital to form ionic bond, where n is the no. </span>of its <span>outermost shell. </span>
Answer:
363C
Explanation:
V = KT and T = V/K
3.5=k(35+273) = 308k
k=3.5/308 =0.011
new T=7.0/0.011=636K = 636-273 =363C
