Given that,
Sample size= 83
Mean number= 39.04
Standard deviation= 11.51
We know the critical t-value for 95% confidence interval which is equal to 1.989.
We also know the formula for confidence interval,
CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))
So, we have
CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)
CI= (39.04 - 2.513,39.04 + 2.513)
CI= (36.527,41.553)
Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).
put ur ASSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS IN UR FATHER
You could make a tree diagram
H T ← 1st toss
H T H T ← 2nd toss
H T H T H T H T ← 3rd toss
etc ,,, then count the combination of favorable outcomes
Using a calculator:
Total number of outcomes is
= 128
Probability of getting exactly 3 heads is found using the follow calculator feature: binompdf(7, 0.5, 3)
ANSWER: Typed into the calculator as follows binompdf(7,0.5,3)×128 =
35
Answer:
843 days
Step-by-step explanation: