Answer:
y = - 2x + 3
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
here m = - 2 and c = 3, hence
y = - 2x + 3 ← equation in slope- intercept form
For this case we have the following functions:
h (x) = 2x - 5
t (x) = 6x + 4
Part A: (h + t) (x)
(h + t) (x) = h (x) + t (x)
(h + t) (x) = (2x - 5) + (6x + 4)
(h + t) (x) = 8x - 1
Part B: (h ⋅ t) (x)
(h ⋅ t) (x) = h (x) * t (x)
(h ⋅ t) (x) = (2x - 5) * (6x + 4)
(h ⋅ t) (x) = 12x ^ 2 + 8x - 30x - 20
(h ⋅ t) (x) = 12x ^ 2 - 22x - 20
Part C: h [t (x)]
h [t (x)] = 2 (6x + 4) - 5
h [t (x)] = 12x + 8 - 5
h [t (x)] = 12x + 3
Answer:
Sorry i am weak but it was so much better to be able and not just to have to do this to be my own and not my life
I'm not sure which numbers you are referring to, but 3 has the same absolute value as -3, and 7 has the same absolute value as -7, just for an example.
You need to prove that <A = <E
since c is the midpoint of line AE then AC = EC
i dont remember the name of the theroem that states that when a triangle has two sides and an angle in common that it is congruent i think it called SAS congruence therom. use that to prove that the <| s are congruent then use CPCTC to prove that <A = <E. then prove that they are || by usint the int angle therom.
