We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)
</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so
</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>
</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>
remember that
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and
1/cos(theta)=sec(theta)-------------> is ok
the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
Answer:
60 km/h
Step-by-step explanation:
Let us use the x to represent the speed of the car since it is the smaller value.
Then, the distance covered by the car is 4x since was going 4 kph.
The distance covered by the train is (x+5) times 7 or 7x+35.
We know that the total distance covered is 640 km.
Using this information, we can set up the equation 4x+7x+35=640.
By subtracting both sides by 35 and combining the x's, we get a new equation of 11x=605.
After this, we divide both sides by 11 and get x=55.
Lastly, we add 5 to 55 since the train is 5 km faster than the car and that x stood for the car.
Train=60 km/h
Answer:a. ii.
A. Is Theoretical because there is no real way of knowing what you will roll.
F(C) = 9/5C + 32
I'll just change F(C) to y and 9/5C to 9/5x.
y = 9/5x + 32
inverse...
x = 9/5y + 32
9/5y = x - 32
y = 5/9x - 160/9
Sooooo
F(C) = 5/9C - 160/9
Answer:
A.\ \ r(d)=-100(d-25)^2+122,500
Hope this helps!