Answer:
three
Step-by-step explanation:
Answer:
By using hypothesis test at α = 0.01, we cannot conclude that the proportion of high school teachers who were single greater than the proportion of elementary teachers who were single
Step-by-step explanation:
let p1 be the proportion of elementary teachers who were single
let p2 be the proportion of high school teachers who were single
Then, the null and alternative hypotheses are:
: p2=p1
: p2>p1
We need to calculate the test statistic of the sample proportion for elementary teachers who were single.
It can be calculated as follows:
where
- p(s) is the sample proportion of high school teachers who were single ()
- p is the proportion of elementary teachers who were single ()
- N is the sample size (180)
Using the numbers, we get
≈ 1.88
Using z-table, corresponding P-Value is ≈0.03
Since 0.03>0.01 we fail to reject the null hypothesis. (The result is not significant at α = 0.01)
Answer:
$5
Explanation:
Since Jerry walked the dog from 6:40am to 7:30am, the total minutes that he walked the dog was 50 minutes. Also a note, an hour is 60 minutes.
Since he is paid at a rate of $6 per 60 minutes, we can make a proportion.
660=x50
From here, you have to solve for x. So cross multiply, and then simplify.
60x=50⋅6
60x60=50⋅6/60
60x60=50⋅6/60
x=5⋅6/6
x=5
So the answer is $5.
(-4)^2-4(1)(5)
16-4(1)(5)
16-4(5)
16-20
-4
The discriminant is negative so there are no real number solutions.