Question

a quantity of ethanol is cooled from 47.9° C to 12.3°C and releases 3.12 KJ of heat. what is the mass of the ethanol sample?​

Answer 1

Answer:

35.9 grams

Step-by-step explanation:

We use the formula:

$q=m*C_p*\Delta T$

Where

q is heat released

m is mass

C_p is the constant 2.44

ΔT is change in temperature

We put the info in the formula and solve for m (mass):

$q=m*C_p*\Delta T\\-3.12 = m*2.44(12.3-47.9)\\-3.12*10^3=m*(-86.864)\\m=35.9$

The mass of ethanol is 35.9 grams