(a^2)^4 = a^8, and (b^3)^4 = b^12. Thus, the quotient is
a^8
--------
b^12
The sum of the sequence is 750
<h3>How to determine the sum of the series?</h3>
The series is given as:
150, 120, 96, and 76.8,
Start by calculating the common ratio using:
r = T2/T1
This gives
r = 120/150
r = 0.8
The sum of the series is then calculated as:
This gives
Evaluate
S = 750
Hence, the sum of the sequence is 750
Read more about sequence at:
brainly.com/question/6561461
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Your multiplying by -4 each time
-1x-4=4
4x-4=-16
-16x-4=64
-12
Mark brainliest please
Hope this helps