Answer:
Part (i) the magnitude of the vector is 5.315 m
Part (ii) the direction of the vector is 138.8⁰
Explanation:
Given;
y-component Ay = 3.50 m
x -component Ax = -4.00 m
Vector representation = (-4i + 3.5j)
Part (i) the magnitude of the vector
Magnitude of the vector = √(-4)² +(3.5)²
Magnitude of the vector = √28.25
= 5.315 m
Part (ii) the direction (in degrees counterclockwise from the +x-axis) of the vector.
If we make a rough sketch of this vector, the direction of this vector lies in second quadrant.
That is; 90 < θ < 180
Let's solve for θ
tan θ = y/x
tan θ = 3.5/-4
tan θ = - 0.875
θ = tan⁻¹ (-0.875)
θ = - 41.2⁰
Since θ lies in the second quadrant,
θ = - 41.2⁰ = 180 - 41.2 = 138.8⁰
The direction of the vector is 138.8⁰
No, because mass is the amount of matter in something and weight is the pull of gravity on a object, for example you would weigh 65 pounds.. and have the mass of 1058..if you were in space your weight would change but your mass will always stay the same
Energy is the ability to do work.
Speed of the tip of the minute hand=V=0.0244 cm/s
Explanation:
The angular velocity of the minute hand is given by
T= time period of the minute hand=60 min=3600 s
so ω= 2 π/3600 rad/s
Now linear velocity v= r ω
r= radius of minute hand=14 cm
so v= 14 (2 π/3600)
V=0.0244 cm/s
Their combined momentum after they meet is 0 .