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2 years ago

Is fire a source of chemical energy

Chemistry

1 answer:

Leno4ka [110]2 years ago

4 0

Answer:

Any matter considered to be a fuel contains chemical energy

Energy has to be provided to initiate the reaction.

So yes. It is

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melamori03 [73]

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2 years ago

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Always carry the microscope with________________-one on the ____________ and one underneath the____________ of the microscope

Ronch [10]

Answer:

Always carry the microscope with two hands. One on the arm and one underneath the base of the microscope.

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2 years ago

Osmotic pressure Π is given by the relation:Π = iMRTwhere i is the van’t Hoff factor, M is the concentration of solute, R is the

lions [1.4K]

Answer: The concentration of solute is 0.503 mol/L

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=icRT$

where,

$\pi$ = osmotic pressure of the solution = 24 atm

i = Van't hoff factor = 2 (for NaCl)

c = concentration of solute = ?

R = Gas constant = $0.08\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the solution = $25^oC=[273+25]=298K$

Putting values in above equation, we get:

$24atm=2\times c\times 0.08\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\c=0.503mol/L$

Hence, the concentration of solute is 0.503 mol/L

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2 years ago

A chemist must prepare 800.0mL of sodium hydroxide solution with a pH of 12.10 at 25°C. She will do this in three steps: Fill a

AnnZ [28]

Answer:

0.42 g

Explanation:

We have:

pH = 12.10 (25 °C)

V = 800.0 mL = 0.800 L

To find the mass of sodium hydroxide (NaOH) we can use the pH:

$14 = pH + pOH$

$pOH = 14 - pH = 14 - 12.10 = 1.90$

$pOH = -log ([OH^{-}])$

$[OH]^{-} = 10^{-pOH} = 10^{-1.90} = 0.013 M$

Now, we can find the number of moles (η) of OH:

$\eta = ([OH]^{-})*V = 0.013 mol/L * 0.800 L = 1.04 \cdot 10^{-2} moles$

Since we have 1 mol of OH in 1 mol of NaOH, the number of moles of NaOH is equal to 1.04x10⁻² moles.

Finally, with the number of moles we can find the mass of NaOH:

$m = \eta * M$

Where M is the molar mass of NaOH = 39.9 g/mol

$m = 1.04 \cdot 10^{-2} moles * 39.9 g/mol = 0.42 g$

Therefore, the mass of sodium hydroxide that the chemist must weigh out in the second step is 0.42 g.

I hope it helps you!

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2 years ago

Calculate the percentage by mass of oxygen in Al2(SO4)3 (Al=27, S=32,O= 16) PLEASE SHOW FULL WORKING

White raven [17]

Answer:

There is 61.538% oxygen in Al2(SO4)3.

Explanation:

Wt Of oxygen in the compound = 12*16 = 192 amu.

Total Wt. Of the compound = 2*12+3*32+12*16 = 312 amu.

Thus, percent of oxygen = Wt of oxygen/total Wt. Of compound *100

= 192/312 * 100=61.538 %

6 0

2 years ago

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Is fire a source of chemical energy￼

Is fire a source of chemical energy