Answer:
C 2
Step-by-step explanation:
This is a parabolic function
Notice how we go negative and then positive
y = ax^2 +bx+c
Let x = 0
-5 = a(0) + b(0) +c
c = -5
y = ax^2 + bx -5
Let x = 3
4 = a(3)^2 +b(3) -5
Let x=-3
4 = a(3)^2 -b(3) -5
Add the two equations
4 = a(3)^2 +b(3) -5
4 = a(3)^2 -b(3) -5
----------------------------
8 = 2a (3)^2 - 10
18 = 2 a(9)
18 = 18a
a =1
Solving for b
4 = 1(3)^2 -b(3) -5
4 = 9 -3b -5
4 = 4 -3b
0 = -3b
0 =b
The equation is
y = (x)^2 -5
Letting y = -1
-1 =x^2 -5
Adding 5 to each side
4 = x^2
Taking the square root of each side
±2 = x
x= ±2
Given the choices
I hope this helps you
1/21+1/28=1/t
4/84+3/84=1/t
5/84=1/t
t=84/5
84/5 1
21 ?
?.84/5=1.21
?=5/4
So you first need to calculate 8y 2 which is basically 8x2 which equals 16 then add 16y + 17y which is 33 so your answer is 33y+2
Answer:
Step-by-step explanation:
First we need the length of the hypotenuse.
20^2 + 21^2 = c^2
400 + 441 = c^2
841 = c^2
29 = c
If you are using angle B as your theta (angle from which the relations are formed:
a) sin = O/H = 20/29
b) cos = A/H = 21/29
c) tan = O/A = 20/21
