№1. Given: r=8 ft, π≈3.14
C=2×π×r=2×3.14×8=50.24=50.2 ft
A=π×r²=3.14×64=200.96=201 ft²
Answer: 50.2 ft; 201 ft²
№2. Given: D=11 cm, π≈3.14
d=2r or r=2/d, so if d is 11 cm, then r is 11÷2=5.5 cm
C=2×π×r=πD=3.14×11=34.54=34.5 cm
A=π×r²=3.14×(5.5)²=94.985=95 cm²
Answer: 34.5 cm; 95 cm²
Step-by-step explanation:
a=20⁰ vertically opposite angles are equal
b=160⁰ sum of angles on a straight line add up to 180⁰
(180⁰-20⁰=60⁰)
c=125⁰ sum of angles on a straight line add up to 180⁰
(180⁰-35⁰-20⁰=125⁰)
Answer:
- g(- x) = - 70 - 3x
Step-by-step explanation:
to evaluate g(- x) substitute x = - x into g(x)
g(- x) = 70 - 3(- x) = 70 + 3x, hence
- g(- x) = - (70 + 3x) = - 70 - 3x
Answer:
- (-1, -32) absolute minimum
- (0, 0) relative maximum
- (2, -32) absolute minimum
- (+∞, +∞) absolute maximum (or "no absolute maximum")
Step-by-step explanation:
There will be extremes at the ends of the domain interval, and at turning points where the first derivative is zero.
The derivative is ...
h'(t) = 24t^2 -48t = 24t(t -2)
This has zeros at t=0 and t=2, so that is where extremes will be located.
We can determine relative and absolute extrema by evaluating the function at the interval ends and at the turning points.
h(-1) = 8(-1)²(-1-3) = -32
h(0) = 8(0)(0-3) = 0
h(2) = 8(2²)(2 -3) = -32
h(∞) = 8(∞)³ = ∞
The absolute minimum is -32, found at t=-1 and at t=2. The absolute maximum is ∞, found at t→∞. The relative maximum is 0, found at t=0.
The extrema are ...
- (-1, -32) absolute minimum
- (0, 0) relative maximum
- (2, -32) absolute minimum
- (+∞, +∞) absolute maximum
_____
Normally, we would not list (∞, ∞) as being an absolute maximum, because it is not a specific value at a specific point. Rather, we might say there is no absolute maximum.