Answer:
Area is 10x^2 - 4x + 6
Step-by-step explanation:
To find this area, multiply the width and height together:
(5x^2 - 2x + 3)(2) = 10x^2 - 4x + 6
8x +9 + 15-8x is -32 it’s that easy
5^(x+7)=(1/625)^(2x-13)
We move all terms to the left:
5^(x+7)-((1/625)^(2x-13))=0
Domain of the equation: 625)^(2x-13))!=0
x∈R
We add all the numbers together, and all the variables
5^(x+7)-((+1/625)^(2x-13))=0
We multiply all the terms by the denominator
(5^(x+7))*625)^(2x+1-13))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x-12))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x=0
not sure if this is right :/
The answer is 9/5
You do 9x1/5 so 9x1 is 9. That’s your numerator and 5x1 is 5 and that’s your denominator
Answer:
y=-2x^2-4
Step-by-step explanation:
The parabola is wider than it's parent function, y = x^2. Therefore the coefficient, of x^2 (when you refer to quadratic equations it's a) should be greater than 1. Let's take 2.
y = 2x^2
Now it is reflected across the x-axis, so the equation turns to y = -2x^2. The vertex is shifted down 4. Note that it is shifted down, along the y-axis. This makes 'c' (again quadratic equations) -4.
Final Equation: y=-2x^2-4