We solve the equation, ( a + a + 1 )^2 = 112 + a^2 + ( a + 1 )^2;
Then, ( 2a + 1 )^2 = 112 + a^2 + a^2 + 2a +1;
4a^2 + 4a + 1 = 113 + 2a^2 + 2a;
Finally, 2a^2 + 2a - 112 = 0;
a^2 + a - 56 = 0;
We use <span>Quadratic Formula for this Quadratic Equation;
The solutions are a1 = 7 and a2 = -8;
But a is a natural number; so, a = 7;
The natural consecutive numbers are 7 and 8.</span>
Answer:y = 3x/4 + 4
Step-by-step explanation:
The equation of a line in the slope-intercept form is represented by
y = mx + c
Where c = y-intercept
Slope, m = change in the value of y on the vertical axis / change in the value of x in the horizontal axis.
change in the value if y is y2 -y1 and change in the value of x is x2 - x1
Where
y2 = final value of y
y 1 = initial value of y
x2 = final value of x
x1 = initial value of x
From the graph,
y2 = 4
y1=0
x2=0
x1 = -3
we can determine the slope.
Slope, m = (4-0) / (0- -3)
= 4/3
Let us pick points (0,4) to determine the intercept
Substituting x = 0 , y = 4 and m = 4/3 into the slope-intercept equation,
y = mx + c
4 = 3/4×0 + c
c = 4
Equation of the line in slope-intercept form is
y = 3x/4 + 4
the mode is the amount/s which occurs most frequently.
In this data set there are 2 values which occur twice
the mode is £254 and £180
The answer will most definitely be C