Evaporation (or another word to use is water vapor.)
Answer:
The mass of the ice block is equal to 70.15 kg
Explanation:
The data for this exercise are as follows:
F=90 N
insignificant friction force
x=13 m
t=4.5 s
m=?
applying the equation of rectilinear motion we have:
x = xo + vot + at^2/2
where xo = initial distance =0
vo=initial velocity = 0
a is the acceleration
therefore the equation is:
x = at^2/2
Clearing a:
a=2x/t^2=(2x13)/(4.5^2)=1.283 m/s^2
we use Newton's second law to calculate the mass of the ice block:
F=ma
m=F/a = 90/1.283=70.15 kg
False! Because the acid rain it becomes a chemicals it does not air get into the rain and up the acidity levels.
Hope it helped you.
-Charlie
:)
Answer:
1.0 m/s
Explanation:
First, convert to SI units.
0.30 km × (1000 m / km) = 300 m
5.0 min × (60 s / min) = 300 s
Speed is distance divided by time:
300 m / 300 s = 1.0 m/s
Answer:
the acceleration of the airplane is 5.06 x 10⁻³ m/s²
Explanation:
Given;
initial velocity of the airplane. u = 34.5 m/s
distance traveled by the airplane, s = 46,100 m
final velocity of the airplane, v = 40.7 m/s
The acceleration of the airplane is calculated from the following kinematic equation;
v² = u² + 2as
Therefore, the acceleration of the airplane is 5.06 x 10⁻³ m/s²
