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2 years ago

The bearing of point B from point A is 064°. Find the bearing of point A from point B.

Mathematics

1 answer:

Alex777 [14]2 years ago

7 0

Answer:

The bearing of A from B is 296 degrees

Step-by-step explanation:

Here, we want to find the bearing of point A from point B

To find the bearing of point A from B, we simply subtract the bearing of B from A from 360

Mathematically, that will be;

360 - 64 = 296 degrees

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Given that x=3sinθ-2 and y=3cosθ+4.Show that (x+2)²+ (y-4)²=9

asambeis [7]

Answer:

First, plug-in x and y as 3sinθ-2 and 3cosθ+4 into the equation, respectively:

$((3\sin (\theta)-2)+2)^2 + ((3\cos (\theta)+4)-4)^2 = 9$

Then, +2 and -2 cancel out and +4 and -4 cancel out as well, leaving you with:

$(3\sin(\theta))^2+(3\cos(\theta))^2=9$

We can factor out 3^2 = 9 from both equations:

$9(\sin(\theta)^2+cos(\theta)^2) = 9$

We know from a trigonometric identity that $\sin(\theta)^2+cos(\theta)^2 = 1$ , meaning we can reduce the equation to:

$9(1) = 9$

$9=9$

And therefore, we have shown that (x+2)^2 + (y-4)^2 = 9, if x=3sinθ-2 and y=3cosθ+4.

Hope this helped you.

7 0

2 years ago

Need help with mean , median , mode question<br> + a few more..

Andreas93 [3]

Answer:

Mean:

a) 4

b) 2

c) 2

d) 2

Median:

a) 4,2

b) 5,2

c) 5,1

d) 4,1

Mode:

a) 1

b) 1

c) 1

d) 1

Step-by-step explanation:

Mean:

a) 1+4+2+1 = 8/4=4

b)1+5+2+1 = 9/4= 2.25 (round to the nearest whole number = 2)

c) 1+5+1+0 = 7/4 = 1.75 (round to the nearest whole number = 2)

d) 1+4+1+0 = 6/4 = 1.5 (round to the nearest whole number = 2)

3 0

2 years ago

Quadrilateral ABCD is a rhombus with an area of 20 square inches.

Ugo [173]

Answer:

area of rhombus =1/2 d1×d2

20=1/2 ×10×d2

d2=4

intersection of diagonal make right angle and cut in equal parts

d1/2=10/2=5

d2/2=4/2=2

use Pythagoras in right angle to bide side

side^2= 5^2 +2^2

side = √29

8 0

2 years ago

How do you solve this

marusya05 [52]

Hope this helps! Good luck!

3 0

3 years ago

25% of American households have only dogs (one or more dogs) 15% of American households have only cats (one or more cats) 10% of

sergeinik [125]

Answer:

a) P=0.2503

b) P=0.2759

c) P=0.3874

d) P=0.2051

Step-by-step explanation:

We have this information:

25% of American households have only dogs (one or more dogs)

15% of American households have only cats (one or more cats)

10% of American households have dogs and cats (one or more of each)

50% of American households do not have any dogs or cats.

The sample is n=10

a) Probability that exactly 3 have only dogs (p=0.25)

$P(x=3)=\binom{10}{3}0.25^30.75^7=120*0.01563*0.13348=0.25028$

b) Probability that exactly 2 has only cats (p=0.15)

$P(x=2)=\binom{10}{2}0.15^20.85^8=45*0.0225*0.27249=0.2759$

c) Probability that exactly 1 has cats and dogs (p=0.1)

$P(x=1)=\binom{10}{1}0.10^10.90^0=10*0.1*0.38742=0.38742$

d) Probability that exactly 4 has neither cats or dogs (p=0.5)

$P(x=4)=\binom{10}{4}0.50^40.50^6=210*0.0625*0.01563=0.20508$

8 0

2 years ago