Answer:
The number of houses built in Town B is 56.
Step-by-step explanation:
We are given that in 2010, the number of houses built in Town A was 25 percent greater than the number of houses built in Town B.
Also, 70 houses were built in Town A during 210.
Let the number of houses built in Town B be 'x'.
So, according to the question;
Number of houses built in Town A = Number of houses built in Town B + 25% of the houses built in Town B
x = 56
Hence, the number of houses built in Town B is 56.
Answer:896.9
Step-by-step explanation:
Let x denotes excess premium over claims
, There are two possibilities
(i)Only husband survives
This can be possible with a possibility of 0.01
Claims=10,000
Premium collected
Thus x=1000-10,000=-9000
(ii)Both husband and wife survives
This can occur with a probability of 0.96
Here claims will be 0 as both survives
Premium taken=1000
thus x=1000
The probability that the husband survives is the sum of above cases
=0.96+0.01=0.97
Hence the desired conditional Expectation
(5/8)+(2/5)=
so you need a common den so in this case its 40
so we multiply to get 40 like
(5/5)(5/8)+ (2/5)(8/8)=
25/40 + 16/ 40 = 41/40