This is a question that would have literally have taken two seconds to look up on google but the answer is 1.88 years.
Answer:
Torque,
Explanation:
Given that,
The loop is positioned at an angle of 30 degrees.
Current in the loop, I = 0.5 A
The magnitude of the magnetic field is 0.300 T, B = 0.3 T
We need to find the net torque about the vertical axis of the current loop due to the interaction of the current with the magnetic field. We know that the torque is given by :
Let us assume that,
is the angle between normal and the magnetic field,
Torque is given by :
So, the net torque about the vertical axis is . Hence, this is the required solution.
Answer:
306500 N/C
Explanation:
The magnitude of an electric field around a single charge is calculated with this equation:
With ε0 = 8.85*10^-12 C^2/(N*m^2)
Then:
E(0.89) = 306500 N/C