For this case we have an equation of the form:
h (t) = - (1/2) * a * t ^ 2 + vo * t + h0
Where,
vo: initial speed
a: acceleration:
h0: initial height.
We have the following equation:
h (t) = - 16t2 + 19t + 110
Therefore, the initial velocity is:
vo = 19 feet / s
Answer:
The initial velocity when the rock is thrown:
vo = 19 feet / s
If width is w the length can be represented as 5/2+2w.
Formula for perimeter is 2l + 2w
So it would be 2w + 2(5/2 + 2w)
OR 2w + 5 + 4w
OR 6w + 5
See if this helps ;)
33km total / 3 hours total = 11 km/hr average
Answer:
2.14 X 10(power4)
Step-by-step explanation: