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Tcecarenko [31]

2 years ago

5

Can someone help find X on the Triangle plssss

1 answer:

Georgia [21]2 years ago

7 0

Answer:

<em>x </em>= 128°

Step-by-step explanation:

Its an isosceles triangle, so it has 2 two sides of equal length. and from here we can say that it has two angles that are the same, 26° and 26° we know that in a triangle there are 180° in total so we add up the two angles we know 26+26=52 and subtract it by 180 which equals 128°

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What is an equation of the line with slope 3/2 and y-intercept −1?

Yuliya22 [10]

Answer:

Aloha,

Hope you are having a wonderful day, y=1.5x-1 is your answer. Hope this helps.

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2 years ago

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Of the 21 children at a park, 5 of them are playing on the swings. What is the approximate

Bond [772]

The Answer Is B

Use proportions to find x% of the children playing on the swings.

$\frac{21}{100} = \frac{5}{x\%}$

$x = 23.80952380\%$

Meaning B is correct.

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2 years ago

Who can't wait for Cyberpunk to come out

andrey2020 [161]

Answer:

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2 years ago

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baherus [9]

Answer: see proof below

<u>Step-by-step explanation:</u>

Given: cos 330 = $\frac{\sqrt3}{2}$

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

$\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}$

Proof LHS → RHS:

LHS cos 165

Double-Angle: cos (2 · 165) = 2 cos² 165 - 1

⇒ cos 330 = 2 cos² 165 - 1

⇒ 2 cos² 165 = cos 330 + 1

Given: $2 \cos^2 165 = \dfrac{\sqrt3}{2} + 1$

$\rightarrow 2 \cos^2 165 = \dfrac{\sqrt3}{2} + \dfrac{2}{2}$

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$\rightarrow \cos^2 165 = \dfrac{2\sqrt3+4}{8}$

Square root: $\sqrt{\cos^2 165} = \sqrt{\dfrac{4+2\sqrt3}{8}}$

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Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

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LHS = RHS $\checkmark$

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2 years ago

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tester [92]

Answer:

Domain:

3,6,12,18

Range:

5,7,9,10

Not a function

Step-by-step explanation:

X= Domain

Y= Range

The input 6 is pared with both 5 and 10

7 0

2 years ago

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