Answer:
Resistencia = 12.5 Ohmios
Explanation:
Dados los siguientes parámetros;
Voltaje = 3.5 Volts
Corriente = 0.28 Amps
Para encontrar el resistencia;
La ley de Ohm establece que a temperatura constante, la corriente que fluye en un circuito eléctrico es directamente proporcional al voltaje aplicado en los dos puntos e inversamente proporcional a la resistencia en el circuito eléctrico.
Matemáticamente, La ley de Ohm viene dada por la fórmula;
Voltaje = corriente * resistencia
Resistencia = voltaje/corriente
Resistencia = 3.5/0.28
Resistencia = 12.5 Ohmios
Por tanto, la resistencia del filamento de una linterna de bolsillo es de 12,5 ohmios.
In the current brainly version, unfortunately you could not change your username.
The only way is to create a new account, but of course all of your points will be gone
For the first part, we are looking for Vf when dy=11.0
Upward is positive, downward is negative.
So <span>Vf = square root [2(-9.8)(11.0) + (18.0)^2] </span>
<span>Vf = 10.4 m/s your answer is correct.
For the part b, t is equals to the time took to reach and dy is equals to 11.0
you did, </span>11= 18t m/s-(1/2) 9.8t^2 then <span>-11 + 18t- 9.8t^2. By quadratic formula, for the way down the answer is 2.9 s while on it's way up, the answer is 0.77 s</span><span>
</span>
Displacement is a vector quantity. So, you incorporate the vector calculations when you try to determine the resultant vector. This is the shortest path from the starting point to the endpoint. If they are moving on one axis only, you use sign conventions. For motions moving to the left, use the negative sign. If it's moving to the right, then use the positive sign. Now, it the object moves 2 km to the left, and 2 km also to the right, the displacement is zero.
Displacement = 2 km - 2km = 0
Generally, the equation is:
<span>Displacement = Distance of motion to the right - Distance of motion to the left</span>
Step by step solution :
standard deviation is given by :
where, is standard deviation
is mean of given data
n is number of observations
From the above data,
Now, if , then
If , then
if , then
If , then
If , then
so,
No, Joe's value does not agree with the accepted value of 25.9 seconds. This shows a lots of errors.