Answer:
x = -0.5
Step-by-step explanation:
From your last step:
6.8x + 9.3 = -2.6 - 17x
We have two terms with x in them on different sides of the equation, so we want to bring the 'x terms' over to the same side.
Add 17x to both sides of the equation.
6.8x + 17x + 9.3 = -2.6
Collect like terms
23.8x + 9.3 = -2.6
Subtract 9.3 from both sides
23.8x = -2.6 - 9.3
23.8x = -11.9
Divide both sides by 23.8
x = -0.5
Answer:
3x-x+2=4
Step-by-step explanation:
Children = x
Adults = y
x + y = 754...1
1.50x + 2.25y = 1422...2
Multiply (1) by 2.25
2.25x + 2.25y = 1696.50...3
1.50x + 2.25y = 1422...2
Subtract (2) from (3)
0.75x = 274.50
x = 366
Substitute x = 366 in (1)
x + y = 754
366 + y = 754
y = 388
366 children and 388 adults swam at the pool.
8 goes into 72 9 times
hope this helped
brainlyist pls
Answer:
10. 9
In the first question we can solve using the Pythagorean theorem. It states that the hypotenuse in a right triangle or the longest side of the triangle, squared is equal to the other 2 sides, squared. Its expressed as so: C^2 = A^2 + b^2 where c is the hypotenuse and a and b are the other sides oft eh triangle.
Therefore,
15^2 = 12^2+x^2
225=144+x^2
81=x^2
x=9
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11. x=12
In this figure, there are 2 right triangles on the sides of the square. If we can find the lengths of the base of both triangles then we can find x using the Pythagorean theorem. the total base is 21 and the square is 11. 11+a+b=21. We can assume that both triangles are congruent and therefore we can solve this equation:
11+a+b=21
a+b=10
5+5=10
b=5
a=5
The bases of the two triangles are 5 and the hypotenuse is 13. Now we can solve using the Pythagorean theorem:
c^2 = a^2+b^2
13^2=5^2+x^2
169=25+x^2
144=x^2
144= 12 x 12
x=12
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12.
The diagnol of a triangle is the hypotenuse and since the length is the square root of 3, we have all the information we need.
c^2 = a^2+b^2
2^2 = (square root of 3)^2+b^2
4=3+b^2
1=b^2
b=1
Step-by-step explanation:
Answer:
Step-by-step explanation:
I'm going to assume that your equation is
So to evaluate it we need to simplify it. Find like terms and perform addition/subtraction on them.