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2 years ago

What is the solution set of x 2 + 5x - 5 = 0?

Mathematics

1 answer:

zalisa [80]2 years ago

7 0

Answer:

a=1 b=5 c=-5

We solve by using the quadratic formula.

x = -5 +- sq root (5² - 4*1*-5) / (2 * 1)

x = [-5 +- sq root (25 + 20)]/ 2

Step-by-step explanation:

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1 year ago

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2 years ago

What is the domain of f?

lana [24]

Answer: C) All real values of x such that $x \le 0$

In other words, x must be 0 or smaller.

===================================================

Explanation:

The reason why is because we must make the stuff under the square root to never be negative. We must make -2x be 0 or larger.

So,

$-2x \ge 0 \\\\-2x+2x \ge 0+2x \ \text{ ... add 2x to both sides}\\\\0 \ge 2x\\\\2x \le 0 \ \text{ ... flip both sides, and the inequality sign}\\\\x \le 0/2 \ \text{ ... divide both sides by 2}\\\\x \le 0$

As an example, if x = -2, then -2x = -2(-2) = 4 is positive. Applying the square root to a positive number is valid.

But if x = 5, then -2x = -2*5 = -10 is under the square root, which is not allowed.

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