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2 years ago

3. (a) Find the elasticity of the demand function p2 + 2p +

Mathematics

1 answer:

NikAS [45]2 years ago

7 0

Answer:

6^2+12+4=49

36+16=49

52=49

therefore.3

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1/3 divided by 2 divided

KatRina [158]

Answer:

1/6

Step-by-step explanation:

1/3 diveded by 2/1

1/3x1/2 = 1/6

Hope it helps:)

6 0

1 year ago

Solve the equation for x. show each step of the solution. name the justifications for each step of the solutions.

sweet [91]

9/2{8-x}+36=102-5/2{3x+24}
you first use 9/2 to open brackets
9/2*8=36,
9/2*x=9/2x
36-9/2x=102-5/2{3x+24}
5/2*3x=15/2x+60
36-9/2x=-15/2x-60
36+60=15/2x+9/2x
96=12x you then divide and the answer obtained will be 8.
x=8

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2 years ago

Please please help me I literally don’t understand this

Orlov [11]

Answer:

n iynoo etindeo soiefijnqaifnqaiwrfofoainjfoiawsfiowoianfqaihjnfoiansn

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Need help with this....

Yakvenalex [24]

Answer:

$\boxed{\dfrac{f(a+h)-f(a)}{h}=-3a^2-3ah-h^2}$

Step-by-step explanation:

$f(x)=-x^3+2\\\\\dfrac{f(a+h)-f(a)}{h}\\\\f(a+h)\to\text{substitute x = a + h}\\f(a)\to\text{substitute x = a}\\\\\dfrac{f(a+h)-f(a)}{h}=\dfrac{-(a+h)^3+2-(-a^3+2)}{h}\\\\\text{use}\ (x+y)^3=x^3+3x^2y+3xy^2+y^3\\\\=\dfrac{-(a^3+3a^2h+3ah^2+h^3)+2-(-a^3)-2}{h}\\\\=\dfrac{-a^3-3a^2h-3ah^2-h^3+2+a^3-2}{h}\\\\\text{combine like terms}$

$=\dfrac{(-a^3+a^3)-3a^2h-3ah^2-h^3+(2-2)}{h}\\\\=\dfrac{-3a^2h-3ah^2-h^3}{h}\\\\=\dfrac{h(-3a^2-3ah-h^2)}{h}\\\\=-3a^2-3ah-h^2$

6 0

2 years ago

Which number is the largest? A. 20.999 B. 21.767 C. 21.76 D. 21.80 E. 21.798

Elza [17]

Answer:

21.80

Step-by-step explanation:

3 0

1 year ago