All categories

1 year ago

Anybody Know This. ?

Mathematics

1 answer:

Pavel [41]1 year ago

3 0

Answer:

7 13/10 cm i think

You might be interested in

Mathematic, please answer<br> solve k: <br> 8k-12=3

poizon [28]

Step-by-step explanation:

8k - 12 = 3

8k = 3 +12

8k = 15

k = 15/8

k = 1.875

4 0

2 years ago

Read 2 more answers

Inessa [10]

Answer:

0.05, 0.5, 0.507, 0.57, 0.577

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

The first 5 terms of a sequence are shown below:

nirvana33 [79]

Step-by-step explanation:

To find the formula for the nth term ,

First , find the common difference or common ratio.

Common difference =

$T_2-T_1 \\ - 2 - 3 \\ = - 5$

Common ratio =

$T_2/T_1 \\ \frac{ - 2}{3}$

The common difference applies to the other given numbers for example :

$T_3- T_2 = - 7 - ( - 2) \\ = - 7 + 2 = - 5$

this proves that it is an arithmetic sequence and the given formula for the nth term of an arithmetic sequence is

T_n =a(n-1)d

Where n = no of terms

a= first term

d= common difference

6 0

2 years ago

How can credit cards be safer than cash? a. It is harder to lose a single credit card than a large number of bills. b. A credit

konstantin123 [22]

Answer: Due to its anonymous nature, if you lose your cash, it's gone. Payment cards can be cancelled and replaced swiftly and remotely. Whilst cash may offer you complete anonymity from data thieves, EMV chip enabled cards offer a more thorough form of payment authentication, providing an extra layer of payment security

So, therefore, C.

3 0

2 years ago

Find the distance traveled by a particle with position (x, y as t varies in the given time interval. x = 3?sin2 t, y = 3?cos2 t,

ANTONII [103]

Assuming the particle's position is given by

$\begin{cases}x(t)=3-\sin2t\\y(t)=3-\cos2t\\0\le t\le4\end{cases}$

then the distance traveled over the interval is

$\displaystyle\int_{t=0}^{t=4}\sqrt{\left(\dfrac{\mathrm dx(t)}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy(t)}{\mathrm dt}\right)^2}\,\mathrm dt$
$=\displaystyle\int_0^4\sqrt{(-2\cos2t)^2+(2\sin2t)^2}\,\mathrm dt$
$=\displaystyle\int_0^4\sqrt{4\cos^22t+4\sin^22t}\,\mathrm dt$
$=\displaystyle2\int_0^4\mathrm dt$
$=2(4-0)=8$

5 0

2 years ago