How much more does the hamster weighs than the mouse is 300 pounds.
Since we have a pet hamster and a pet mouse. We know that the hamster weighs 416 of a pound and the mouse weighs 116 of a pound.
To know how much more the hamster weighs more than the mouse, we take the difference between the weight of the hamster and the weight of the mouse.
Since the weight of the hamster = 416 pounds and the weight of the mouse equals 116 pounds.
<h3>The difference in weight</h3>
The difference in the weight d = weight of hamster - weight of mouse
= 416 pounds - 116 pounds
= 300 pounds.
So, how much more does the hamster weighs than the mouse is 300 pounds.
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Hi I am here to help the answer is 46-90
Answer:
Step-by-step explanation:
Let the angles be 4x , 5x
4x + 5x = 180 { supplementary}
9x = 180
x = 180/9
x = 20
Larger angle= 5x = 5* 20 = 100
Answer:
5 and a half
Step-by-step explanation:
Because you can fit 2 liters in each can, to find how many you would need, divide 11 by 2, this would give you 5 and a half, 5.5.
It could be that they want you to round up to six or round down to five, so do consider that.
It is given in the question that
A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by
And the edge length of the base is 12 cm, the edge length of the base is decreasing at a rate of 2 cm/min, the height of the box is 6 cm, and the height is increasing at a rate of 1 cm/min.
Here we differentiate V with respect to t, and we use product rule, that is
Substituting the given values , we will get
![[tex]dV/dt = 2(12)(6)(-2)+ 12^2(1)](https://tex.z-dn.net/?f=%5Btex%5DdV%2Fdt%20%3D%202%2812%29%286%29%28-2%29%2B%2012%5E2%281%29)
[/tex]
So at that moment, the volume is decreasing at the rate of
