11 runners took at least 30 minutes to finish the race. (:
Answer:
Proved
Step-by-step explanation:
To prove that every point in the open interval (0,1) is an interior point of S
This we can prove by contradiction method.
Let, if possible c be a point in the interval which is not an interior point.
Then c has a neighbourhood which contains atleast one point not in (0,1)
Let d be the point which is in neighbourhood of c but not in S(0,1)
Then the points between c and d would be either in (0,1) or not in (0,1)
If out of all points say d1,d2..... we find that dn is a point which is in (0,1) and dn+1 is not in (0,1) however large n is.
Then we find that dn is a boundary point of S
But since S is an open interval there is no boundary point hence we get a contradiction. Our assumption was wrong.
Every point of S=(0, 1) is an interior point of S.
First, set the coordinate points on a graph, and joint them to form a graph
By looking at the graph we can see that:
width : 3
length: 6
Area of a rectangle : Length x width : 6 x 3 = 18
12748 rounded to the nearest thousand is 13000
Answer:
Step-by-step explanation:
We are given that c=6 units
We have to find the side length a and b.
We know that sum of angles of a triangle =180 degrees
Substitute the values then we get
sine law: