The temperature outside a plane flying at an altitude of 5 kilometers is -17°C.
Given that,
- The ground temperature at the airport is 10 °C.
- The decrease in temperature is 5.4°C for each & every rise in 1 kilometer.
Based on the above information, the temperature outside should be
The decrease in the temperature should be
= 5.4×5
= 27°C
Now the final temperature is
= 10 - 27
= -17°C
Therefore we can conclude that the temperature outside a plane flying at an altitude of 5 kilometers is -17°C.
Learn more: brainly.com/question/20459283
Answer:
9(254.34 in. 2)
and
7ft
Step-by-step explanation:
Answer:
y= 11/2 x+1/2
Step-by-step explanation:
Slope Intercept form: y = mx + b where m = slope of the line, b = y intercept and (x,y) are coordinate points on the line.
To put this in slope-intercept form, you need to solve the equation for y
-11x + 2y = 1
<u>+11x +11x</u> add 11x to both sides of the equation
<u>+2y</u> = <u>1 + 11x</u>
2 2 Divide both sides by 2 (so y is by itself)
y = 11/2x + 1/2
Answer:
1 is inequality
replace the value were _2.
Answer:
Step-by-step explanation:
Value of Sam's car after t years =
=
Value of Sam's car in 5 years=
= $ 4437
