3. Which of the following affects the angle at which the sun's rays hit Earth?

11.9 g Cl2 is reacted with 10.7 g NaOH. How many moles of NaCl are produced?

melisa1 [442]

Answer:

1. 7.256g of NaCl

2. 47.33g of Cl2

Explanation:

2 moles of Na reacts to produce 2 moles of NaCl

8 moles of Na will still produce 8 moles of NaCl

Mass of NaCl = molar mass of Nacl/moles of Nacl

=58.5/8

=7.256g of NaCl

From the equation, 2 moles of Na reacts with 1 mole of Cl2

3/2 moles of Cl2 will react with 3 moles of Na

Mass of Cl2 = 71/1.5

=47.33g of Cl2

Explanation:

4 0

2 years ago

Jacob is doing a report on the galaxy in which Earth is found. Which of the following is the galaxy that Jacob should research f

vichka [17]

Answer:

milky way

Explanation:

3 0

2 years ago

Molybdenum has a molar mass of 95.94g/mol. How many molecules of molybdenum are in 150.0 g of molybdenum

Kitty [74]

We are given the molar mass of Molybdenum as 95.94 g/mol. Also, the chemical symbol for Molybdenum is Mo. This question is asking for the amount of molecules of molybdenum in a 150.0 g sample. However, since molybdenum is a metal and it is in the form of solid molybdenum, Mo (s), it is not actual a molecule. A molecule has one or more atom bonded together. We will instead be finding the amount of atoms of Molybdenum present in the sample. To do this we use Avogadro's number, which is the amount of atoms/molecules of a substance in 1 mole of that substance.

150.0 g Mo/ 95.94 g/mol = 1.563 moles of Mo

1.563 moles Mo x 6.022 x 10²³ atoms/mole = 9.415 x 10²³ atoms Mo

Therefore, there are 9.415 x 10²³ atoms of Molybdenum in 150.0 g.

5 0

2 years ago

7. NH2CO2NH4(s) when heated to 450 K undergoes the following reaction to produce a system which reaches equilibrium: NH2CO2NH4(s

Taya2010 [7]

Answer:

Value of equilibrium constant is 0.0888

Explanation:

Both $NH_{3}$ and $CO_{2}$ are gaseous. Hence equilibrium constant depends upon partial pressures of $NH_{3}$ and $CO_{2}$ .

Initially no $NH_{3}$ and $CO_{2}$ were present.

Hence mole fraction of $NH_{3}$ and $CO_{2}$ at equilibrium can be calculated from coefficient of $NH_{3}$ and $CO_{2}$ in balanced equation.

Mole fraction of $NH_{3}$ = (number of moles of $NH_{3}$ )/(total number of moles of $NH_{3}$ and $CO_{2}$ ) = $\frac{2moles}{(2+1)moles}=\frac{2}{3}$

Mole fraction of $CO_{2}$ = (number of moles of $CO_{2}$ )/(total number of moles of $NH_{3}$ and $CO_{2}$ ) = $\frac{1moles}{(2+1)moles}=\frac{1}{3}$

Let's assume both $CO_{2}$ and $NH_{3}$ behaves ideally.

Therefore partial pressure of $NH_{3}$ , $P_{NH_{3}}= x_{NH_{3}}.P_{total}$ and P_{CO_{2}}= x_{CO_{2}}.P_{total}

Where x represents mole fraction

So, $P_{NH_{3}}=\frac{2}{3}\times 0.843atm=0.562atm$

$P_{CO_{2}}=\frac{1}{3}\times 0.843atm=0.281atm$

So, $K_{p}=P_{NH_{3}}^{2}.P_{CO_{2}}=(0.562)^{2}\times 0.281=0.0888$

4 0

2 years ago

Identify 3 physical changes that could occur with a sheet of paper

VladimirAG [237]

Answer:

1. Dimensions: The sheet can be cut into several smaller pieces.

2. Shape: the sheet can be formed into a paper ball or any other shape (using origami for example).

3. Color: You can use crayons to paint the sheet and change its color.

Explanation:

Physical changes do not change the chemical properties. They do not transform the compounds that form the substances. They do not break and or form chemical bonds.

When you change the form, the state (solid, liquid or gas), the color, you are just changing physical properties.

Only chemical changes change the compounds that form the substance. For instance, if you burn the sheet of paper, then you are causing a chemical change because the organic matter in the paper will react with oxygen forming CO₂ and water, but by cutting, folding, smashing, or coloring with crayons, the compounds in the sheet of paper do not change.

6 0

2 years ago