Find all the roots of the polynomial equation
x^3-2x^2+5x-10=0
2 answers:
Step-by-step explanation:
x^3+x^2+4x+4=0
x³+x²+4x=-4
x(x²+x+4)=-4
either
x=-4
or
x²+x+4=-4
x²+x+4+4=0
x²+x+8=0
comparing with ax² +bx+c
a=1
b=1
c=8
x={-1±√{1²-4×1×8}}/2×1
x={-1±√{-31}}/2
x³ - 2x² + 5x - 10 = 0
x²(x - 2) + 5(x - 2) = 0
(x² + 5)(x - 2) = 0
x² = - 5 , x = 2.
x² = -√5 , 2.
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Answer:
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Step-by-step explanation:
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Answer:
Step-by-step explanation:
multiply constants and add the exponents
Answer:
-6x + 21
Step-by-step explanation:
9 - 3(2x - 4)
9 - 6x + 12
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Assuming the order doesn't matter it would be 10c6 = 210 ways
