Sin50° = BC/3
3sin50° = BC
BC = 2.981
Hope this helped!
I'm not sure what this question means exactly, maybe the principals goal is unrealistic?
Maybe, 150-100=50 on each triangular side. 50*height(80)=4000 divided by 2=2000. 2000 *'s 2, since we have to count the other side. Now, we have 100 left. so top of rectangle,(48 ft) times what's left of height. 48*(80-64=16) 16=768. Which covers the width of the big column, (48) and leftover height. Next, we find out the 2 left columns, one on each side of rectangle. Find area of rectangle, (what's left) 100. 100*80=800. 800- area of rectangle. Area of rectangle= 3072. Almost lastly, 4000 plus 800= 4800, then, 4800-3072=1728. I believe that the correct answer for the area of the lawn is 1,728 feet.
2.50 - 3.10 - 3.86 + 2.70 - 4.01 =
-6.30
So; the answer is -6.30.
Verbal model: mile/inch=mile/inch
Proportion: 7/8÷3/10=x/1
Solve= 7/8*10/3=x/1
70/24=x/1
70=24x
x=35/12
The unit rate must be