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2 years ago

Busca información acerca de si las siguientes sustancias son simples o

Chemistry

1 answer:

vazorg [7]2 years ago

7 0

Answer:

a) El cobre es un elemento químico de los denominados metales de transición. El cobre encabeza el grupo de los metales nobles: cobre, plata y oro. Los átomos de cobre tienen 29 protones y 29 electrones. El cobre tiene dos isótopos naturales estables: uno tiene 34 neutrones y el otro, 36. Es una sustancia simple

b) Los elementos químicos que componen el azufre es el fósforo y el cloro. Es una sustancia Simple.

c) El azucar o tambien llamado sacarosa (C12H22O11) esta compuesto de carbono, hidrogeno y oxigeno. Es una sustancia compuesta

d) Las fuentes principales de donde se obtienen los alcoholes son las siguientes: Fermentación de Carbohidratos: Los azucares y almidones, que a su vez provienen de los vegetales-caña de azúcar, cebada, maíz, etc-, al fermentar por acción de las levaduras producen alcohol etílico. Es una sustancia. Tanto el alcohol como la acetona son sustancias compuestas.

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Answer:

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Explanation:

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To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple _______. Then, plot ln(K

Aloiza [94]

Answer:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:

$\Delta G=-RTln(Ksp)\\\\\Delta G=\Delta H-T\Delta S$

Thus, by combining them, we obtain:

$-RTln(Ksp)=\Delta H-T\Delta S\\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{T\Delta S}{RT} \\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{\Delta S}{R}$

Which is related to the general line equation:

$y=mx+b$

Whereas:

$y=ln(Ksp)\\\\m=-\frac{\Delta H}{R} \\\\x=\frac{1}{T} \\\\b=\frac{\Delta S}{R}$

It means that we answer to the blanks as follows:

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