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2 years ago

Solve the following system of equations.

Mathematics

2 answers:

DIA [1.3K]2 years ago

7 0

2x+y-3=0,x-2y=1 okay that's the answer good luck

Elanso [62]2 years ago

5 0

Subtract y from both sides
now we have
2x = -y + 3
divide both sides by 3
x= -y/2 + 3/2
the other x equals 2y +1, set these equal to eachother

2y + 1 = -y/2 + 3/2

add y/2 to both sides

2.5y + 1 = 3/2

subtract 1 from both sides

2.5y = 0.5

divide both sides by 2.5

y=0.2

plug in 0.2 for y in an original equation

x = 2(0.2) + 1

solve

x = 1.4

ANSWER:
x= 1.4
y= 0.2

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Firdavs [7]

Given:

A figure of a parallelogram.

The vertex angles are $(12b+8)^\circ,(5b+2)^\circ,2a^\circ$ .

To find:

The values of a and b.

Solution:

We know that the pairs of consecutive angles of a parallelogram are supplementary angles. It mean their sum is 180 degrees.

$(12b+8)^\circ+(5b+2)^\circ=180^\circ$ (Supplementary angles)

$(17b+10)^\circ=180^\circ$

$17b+10=180$

Subtract 10 from both sides.

$17b=180-10$

$17b=170$

Divide both sides by 17.

$b=\dfrac{170}{17}$

$b=10$

Now,

$(5b+2)^\circ=(5(10)+2)^\circ$

$(5b+2)^\circ=(50+2)^\circ$

$(5b+2)^\circ=52^\circ$

And,

$(5b+2)^\circ+2a^\circ=180^\circ$ (Supplementary angles)

$52^\circ+2a^\circ=180^\circ$

$2a^\circ=180^\circ-52^\circ$

$2a^\circ=128^\circ$

Divide both sides by 2.

$a^\circ=\dfrac{128^\circ}{2}$

$a^\circ=64^\circ$

$a=64$

Therefore, the value of a is 64 and the value of b is 10.

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2 years ago

What are the factors of the square root of 329

Andru [333]

Answer: $x=-\dfrac{3}{2}, 7$

Step-by-step explanation:

$2x^2-10x-26=x-5$

$2x^2-10x-26-x+5=0$ Move all terms to one side

$2x^2-11x-21=0$ Simplify $2{x}^{2}-10x-26-x+5$

$2x^2+3x-14x-21=0$ Split the second term

$x(2x+3)-7(2x+3)=0$ Factor out common terms in the first two terms, then in the last two terms.

$(2x+3)(x-7)=0$ Factor out the common term $2x+3$

$x=-\dfrac{3}{2}, 7$

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2 years ago

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pentagon [3]

Answer:

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Step-by-step explanation:

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2 years ago

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1. AB = 11 and BC = 5. Find AC 2. AC = 16, BC = x + 4, AB = x + 14. Find x

lord [1]

The wording of the question kinda doesn't make sense in some parts, but I'll try anyway. 1 plus 4 is 5, and since BC is 5, x is 1 for BC. -3 plus 14 is 11, so x is -3 for AB.

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