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2 years ago

What is 3 divided by 1/4

Mathematics

2 answers:

fgiga [73]2 years ago

5 0

Answer:

Step-by-step explanation:

multiply by the reciprocal of the fraction

3×4

=12

konstantin123 [22]2 years ago

4 0

12 have a nice day plz mark as brainliest

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Hi, I need help with how it work out the angles on this please

kap26 [50]

All the angles in any triangle add up to make 180°.

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2 years ago

9y = 3y Combine the like terms

-BARSIC- [3]

9y-3y=0
6y=0

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2 years ago

The difference of a number s and 6

Luda [366]

Answer:

idk

Step-by-step explanation:

What you do you have to find someone more smarter than me!

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2 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

2 years ago

Can you exchange the coordinates of points ( x 1, y 1) and ( x 2, y 2) in the distance formula and still find the correct distan

notka56 [123]

Answer:

yes

Step-by-step explanation:

As an example

(x₁, y₁ ) = (1,2) and (x₂, y₂ ) = (5,3), then

d = $\sqrt{(5-1)^2+(3-2)^2}$ = $\sqrt{4^2+1^2}$ = $\sqrt{16+1}$ = $\sqrt{17}$

Now let (x₁, y₁ ) = (5,3) and (x₂, y₂ ) = (1,2), then

d = $\sqrt{(1-5)^2+(2-3)^2}$ = $\sqrt{(-4)^2+(-1)^2}$ = $\sqrt{16+1}$ = $\sqrt{17}$

3 0

2 years ago