First solve the length of side BC, CD, EF and FA
Since BC = CD = sqrt( 10^2 + 10^2)
BC = CD = 14.1421
FA = EF = sqrt(10^2 + 20^2)
= 23.3607
So the perimeter = 10 + 10 + 14.1421 + 14.1421 + 23.3607
= 93
The area is made up be triangle FAE, rectangle ABDE and
triangle BCD
A = 0.5(20)(20) + (10)(20) + 0.5(20)(10)
<span>A = 500 sq units</span>
By the general application of cumulative property of addition :
x + y = y + x
For sure
We need to FOIL that out and then get it into standard form to see what our A, B, and C are. FOILing gives us
. If we move the 7 over by subtraction and set it equal to 0, we have
. In order to avoid a negative leading coefficient, we can change all the signs to get
so A = 1, B = 0, C = -18, first choice above.
Answer:
A
Step-by-step explanation:
We want to find the surface area, which will essentially just be the areas of all the figures given in the net.
We have two congruent triangles and 3 different rectangles.
<u>Triangles</u>:
The area of a triangle is denoted by: A = (1/2) * b * h, where b is the base and h is the height. The base here is 3 and the height is 4, so:
A = (1/2) * b * h
A = (1/2) * 3 * 4 = 6
Since there are two triangles, multiply 6 by 2: 6 * 2 = 12 cm squared
<u>Rectangles</u>:
The area of a rectangle is denoted by: A = b * h, where b is the base and h is the height.
The base of the leftmost rectangle is 4 and the height is 7, so:
A = b * h
A = 4 * 7 = 28
The base of the middle rectangle is 3 and the height is 7, so:
A = b * h
A = 3 * 7 = 21
The base of the rightmost rectangle is 5 and the height is 7, so:
A = b * h
A = 5 * 7 = 35
Add these together:
12 + 28 + 21 + 35 = 96 cm squared
The answer is thus A.
