Answer:
3(4a−5b+2)
Step-by-step explanation:
The answer should have originally been 3(4a-5b+2)
3(4a+5b+3)= 12a+15b+9 which is incorrect.
For 3/9, the repeating decimal is .3
P(at least 5 rolls until 1) = P(4 rolls are not 1) = 5/6 x 5/6 x 5/6 x 5/6 = 0.4823 (4sf)
Fewer than 7 rolls to get second 1 after first takes 3 rolls means second occurs on 4th, 5th or 6th roll
The probability of each of these is 1/6, 5/6 x 1/6 and 5/6 x 5/6 x 1/6 respectively.
P(second 1 on 4th, 5th or 6th roll) = 1/6 + 5/36 + 25/216 = 91/216 = 0.4213 (4sf)
Answer:
6.10%
Step-by-step explanation:
For every round since we are choosing with equal probability, then the probability of choosing from either of the bags is 1/2
Here, this scenario is only possible when a particular bag has been chosen 10 times and the other bag has been chosen 6 times ( meaning a particular bag has been emptied and for a particular bag to be emptied, all of its content would have been picked)
Now on the 17th trial, an empty bag is chosen
Therefore the required probability will be;
16C0 * (1/2)^10 * (1/2)^6 * 1/2 = 0.0610 = 6.1%
Answer:
5,800m
Step-by-step explanation:
1 km = 1000 m
Use the SBD (small to big, divide) and BSM (big to small, multiply) method.
So, 5.8 X 1000, as we are converting km(big) to m(small) and move the decimal point corresponding to the number of zeroes = 5800m
