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2 years ago

What size volumetric flask would you use to create a 1.00M solution using 166.00 g of KI?

Chemistry

1 answer:

mr Goodwill [35]2 years ago

3 0

Answer:

A 1 liter volumetric flask should be used.

Explanation:

First we convert 166.00 g of KI into moles, using its molar mass:

Molar mass of KI = Molar mass of K + Molar mass of I = 166 g/mol

166.00 g ÷ 166 g/mol = 1 mol KI

Then we calculate the required volume, using the definition of molarity:

Molarity = moles / liters

Liters = moles / molarity

1 mol / 1.00 M = 1 L

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Vlada [557]

Stoichiometry of the reaction:

2 KClO₃ = 2 KCl + 3 O₂
 ↓ ↓

2 mole KClO₃ ----------> 3 mole O₂
2 mole KClO₃ ----------> ?

KClO₃ = 2 * 3 / 2

KClO₃ = 6 / 2

= 3 moles de KClO₃

hope this helps!

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2 years ago

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Mars2501 [29]

The fact that CO2 is released from oceans due to further rise in temperature is an example of a negative feedback.

A negative feedback is one in which the process that produces the feedback is interrupted. That is, the process is stopped as a result of the feedback received.

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2 years ago

Two common materials we encounter in our daily lives are radiator coolant in automobiles and dry ice. The coolant in an automobi

Yuki888 [10]

Answer:

See explanation

Explanation:

Using the formula

°C = (F-32) × 5/9

Where;

°C = temperature in degrees centigrade

F= temperature in Fahrenheit

F= (9/5 ×°C) +32

F= (9/5 × 110) + 32

F= 230°F

To convert -78°C to Kelvin

-78°C + 273 = 195 K

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3 years ago

KCI is a molecule. True or False

Monica [59]

Answer: duh

Explanation:

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2 years ago

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A 2.5 L container holds a sample of hydrogen gas at 291 K and 180 kPa.

netineya [11]

Answer:

The new temperature will be 565.83 K.

Explanation:

Gay Lussac's law establishes the relationship between the temperature and the pressure of a gas when the volume is constant. This law says that the pressure of the gas is directly proportional to its temperature. This means that if the temperature increases, the pressure will increase; or if the temperature decreases, the pressure will decrease.

In other words, Gay-Lussac's law states that when a gas undergoes a constant volume transformation, the ratio of the pressure exerted by the gas temperature remains constant:

$\frac{P}{T} =k$