Distance = sqrt(5- -6)^2 + (3- -6)^2)
= sqrt (121 + 81)
= sqrt 202
= 14.21 to nearest hundredth
Answer:
The volume of the concentrated 80 gallons mixture is 20 gallons
The volume of water in the 80 gallons mixture is 60 gallons
Step-by-step explanation:
The given parameters are;
The content of Container A = The cleaner
The concentration of the cleaner = 20% solution
The content of Container B = Pure water
The concentration of the desired solution = 5%
The volume of the required solution = 80 gallons
Let x represent the volume of the concentrated solution and y represent the volume of water in the 80 gallons mixture
Therefore, we have;
20/100 × x + y×0 = 5/100×80
x + y = 80
y = 80 - x
20/100 × x + (80 - x)×0 = 5/100×80
0.2·x = 4
x = 4/0.2 = 20
x = 20 gallons
y = 80 - x = 80 - 20 = 60
y = 60 gallons
The volume of the concentrated solution (80 gallons mixture) = x = 20 gallons
The volume of water in the 80 gallons mixture = y = 60 gallons.
Since both the input and the output assume only integer values, the function is classified as discrete.
<h3>What are continuous and discrete variables?</h3>
- Continuous variables: Can assume decimal values, hence they are represented by rational numbers.
- Discrete variables: Assume only countable values, such as 1, 2, 3, …, hence they are represented by whole numbers, or even integers if it can be negative.
In this problem, all values on the table assume only integer values, hence the function is classified as discrete.
More can be learned about classification of variables at brainly.com/question/16978770
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2.8-(-5.1)
-(-5.1)=5.1
2.8+5.1= 7.9
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