Answer:
0.00627 :)
Step-by-step explanation:
Using the z-distribution, the 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:
In which:
- is the sample proportion.
In this problem, we have a 99% confidence level, hence, z is the value of Z that has a p-value of , so the critical value is z = 2.575.
The estimate and the sample size are given by:
.
Then the bounds of the interval are:
The 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).
More can be learned about the z-distribution at brainly.com/question/25890103
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The bank account owner is withdrawing money at the rate of $50/month. The account balance is steadily declining.
Answer:
Correct option: b 39.
Step-by-step explanation:
A one-sample (or one mean) t-test is applied to test whether the population-parameter is significantly different from some hypothetical value.
The degrees of freedom of the <em>t</em>-test is:
df = n - 1
It is provided that the sample size is, <em>n</em> = 40.
Compute the degrees of freedom as follows:
df = n - 1
= 40 - 1
= 39
Thus, the correct option is b.
Misread!!!
A^2+B^2=C^2
A=B because both angles 45 degrees
5^2+5^2=C^2
25+25=C^2
x=5
y=sqrt (50)