0=40-10t-5t^2
t^2+2t-8=0
(t+4)(t-2)=0
t=-4 (not a solution) or t=2
Answer: after 2 seconds
Answer:
Think it is D I am not sure
Step-by-step explanation:
we know that
The measurement of the exterior angle is the semi-difference of the arcs which comprises
In this problem
∠FGH is the exterior angle
∠FGH=
∠FGH=
-----> equation A
--------> equation B
Substitute equation B in equation A
![100\°=(arc\ FEH-[360\°-arc\ FEH])](https://tex.z-dn.net/?f=100%5C%C2%B0%3D%28arc%5C%20FEH-%5B360%5C%C2%B0-arc%5C%20FEH%5D%29)
therefore
<u>The answer is</u>
The measure of arc FEH is equal to 
Answer:
each tube costs $1.5 so put it the point in between 1 and 2
thank you
Step-by-step explanation:
Answer:
The height of the cylinder is 4x units.
Step-by-step explanation:
volume of a cylinder = nr^2h
n = 22/7
r = radius = x/2
Let illustrate with an example. If the diameter of a cylinder is 6 and the volume is 6^3 = 216. The radius = 6/2 = 3
n3^2 x h = 216
h = 216/9 = 24
so the height is 4 times the diameter
Area of the base = nr^2
1/2^2 x x = 1/4 pi x^2
