The rigth equation to anticipate the profit after t years is p(t) = 10,000 (1.075)^t
So, given that both store A and store B follow the same equations but t is different for them, you can right:
Store A: pA (t) 10,000 (1.075)^t
Store B: pB(t'): 10,000 (1.075)^t'
=> pA(t) / pB(t') = 1.075^t / 1.075^t'
=> pA(t) / pB(t') = 1.075 ^ (t - t')
And t - t' = 0.5 years
=> pA(t) / pB(t') = 1.075 ^ (0.5) = 1.0368
or pB(t') / pA(t) = 1.075^(-0.5) = 0.964
=> pB(t') ≈ 0.96 * pA(t)
Which means that the profit of the store B is about 96% the profit of store A at any time after both stores have opened.
999.1 is the answer you multiply both then add
Answer:
0.79
Step-by-step explanation:
add up the probability that is less than or equal to 0, which is 0.17+0.13+0.33+0.16 = 0.79
Answer:
a<-3
bc -3(-2)=6
so if u go lower which the next number would be -4(-2)=8 which is greaterthan 6
Step-by-step explanation:
Answer:
the cost for each gallon is 2.59
Step-by-step explanation:
