Answer:
The answer is A. t = 0.4n
Step-by-step explanation:
<em>See how on the graph, when n is 2, t is around 1? We just plug in 2 into n into the equation, t=0.4n. 0.4 times 2 is 0.8, so t=0.8. 0.8 is around 1, so a is right.</em><em> </em>If we tried the same thing with one of the other choices, like B. t=2.5n, then plugging in 2 into n would give us 2 times 2.5, which is 5. 5 is nowhere around 1, making it wrong.
First you have to have the absolute value isolated so the 2 has to be divided. Then set up the two cases and solve.
We can substitute<span> y in the second </span>equation<span> with the first </span>equation<span> since y = y. The solution of the </span>linear<span> system is (1, 6). You can use the </span>substitution method<span> even if both </span>equations<span> of the </span>linear<span> system are in standard form. Just begin by solving one of the </span>equations<span> for one of its variables.</span>
The answer is x^2y^2/5x^2 / 20.