Answer:
Part a)
the tension force is equal to the weight of the crate
Part b)
tension force is more than the weight of the crate while accelerating upwards
tension force is less than the weight of crate if it is accelerating downwards
Explanation:
Part a)
When large crate is suspended at rest or moving with uniform speed then it is given as
here since speed is constant or it is at rest
so we will have
so the tension force is equal to the weight of the crate
Part b)
Now let say the crate is accelerating upwards
now we can say
so tension force is more than the weight of the crate
Now if the crate is accelerating downwards
so tension force is less than the weight of crate if it is accelerating downwards
The Answer is D
Because you add all of them to equal 9 atoms
Answer: 1175 J
Explanation:
Hooke's Law states that "the strain in a solid is proportional to the applied stress within the elastic limit of that solid."
Given
Spring constant, k = 102 N/m
Extension of the hose, x = 4.8 m
from the question, x(f) = 0 and x(i) = maximum elongation = 4.8 m
Work done =
W = 1/2 k [x(i)² - x(f)²]
Since x(f) = 0, then
W = 1/2 k x(i)²
W = 1/2 * 102 * 4.8²
W = 1/2 * 102 * 23.04
W = 1/2 * 2350.08
W = 1175.04
W = 1175 J
Therefore, the hose does a work of exactly 1175 J on the balloon
Potential and kinetic energy are the two types of energy, but they do get separated into subgroups, for which I do not know. Hope that helps.