Andrew can buy maximum 3 meals this weekend.
From given question,
Andrew must spend less than 53$ on meals during the weekend.
He has already spent 21$ on meals costing 8$ average.
Let x, the number of meals
So, we get an inequality,
8x + 21 < 53
We need to find the number of meals he can buy this weekend.
From above inequality,
⇒ 8x + 21 < 53
⇒ 8x < 53 - 21
⇒ 8x < 32
⇒ x < 4
This means, from 1 to 3 meals.
Therefore, Andrew can buy maximum 3 meals this weekend.
Learn more about an inequality here:
brainly.com/question/19003099
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Answer:
1). 0.903547
2). 0.275617
Step-by-step explanation:
It is given :
K people in a party with the following :
i). k = 5 with the probability of
ii). k = 10 with the probability of
iii). k = 10 with the probability
So the probability of at least two person out of the 'n' born people in same month is = 1 - P (none of the n born in the same month)
= 1 - P (choosing the n different months out of 365 days) =
1). Hence P(at least 2 born in the same month)=P(k=5 and at least 2 born in the same month)+P(k=10 and at least 2 born in the same month)+P(k=15 and at least 2 born in the same month)
=
=
= 0.903547
2).P( k = 10|at least 2 share their birthday in same month)
=P(k=10 and at least 2 born in the same month)/P(at least 2 share their birthday in same month)
=
= 0.0.275617
Yes, since you can multiply 2/5 numerator and denominator to get the rest of the fractions, it makes them all equivalent.
Answer:
radius= 7
Step-by-step explanation:
the radius is half of the diameter.
i hope this helps :)