What is the value of b2 - 4ac for the following equation? 2x 2 - 2x - 1 = 0

1 answer:

6 0

For you to make an equation a quadratic equation, you need everything to be on one side, so you add one to both sides.

2x^2 + 3x + 0=0 

a=2, b=3, c=0 

b^2-4ac (In the next step just plug in your variables) 

3^2 - 4(2)(0) 

9 - 8(0) 

9 - 0 

Your answer=9

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Which of the following is the equation of a circle with a radius of 10 cm and center at (–3, 6)?

Volgvan

The equation of the circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have:

$r=10\\(-3,\ 6)\to h=-3,\ k=6$

Substitute:

$(x-(-3))^2+(y-6)^2=10^2\\\\(x+3)^2+(y-6)^2=100$

4 0

2 years ago

Name two solutions for each inequality.

ahrayia [7]

So,

#1: $n \geq 3 \frac{11}{16} + 4 \frac{1}{2}$

Convert to like improper fractions.
$n \geq \frac{59}{16} + \frac{72}{16}$

Add.
$n \geq \frac{131}{16}\ or\ 8 \frac{3}{16}$

So, one solution could be $8 \frac{3}{16}$ .

Another solution could by 9. There is also 10, 11, 12, etc., and all numbers in between.

#2: $k \ \textless \ 6 \frac{2}{5} * 15$

Convert into improper fraction form.
$k \ \textless \ \frac{32}{5} * 15$

Multiply.
$\frac{(2^5)(3)(5)}{5}$

Cross-cancel, and we have our final result.
$(2^5)(3) = 96$
k < 96

96 is not a solution.

95 is a solution.

So is 94, 93, 92, etc, and all numbers in between.

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2 years ago

3x-8<-2x+22 Show it with steps please.

Neko [114]

Answer:

x < 6

Step-by-step explanation:

1. 3x+2x = 5x

2. 5x - 8 < 22

3. 22+ 8 =30

4. 5x < 30

5. 30/5 = 6