Answer:
A.)
H0: μ ≤ 31
H1: μ > 31
B.)
H0: μ ≥ 16
H1: μ < 16
C.)
Right tailed test
D.)
If Pvalue is less than or equal to α ; we reject the Null
Step-by-step explanation:
The significance level , α = 0.01
The Pvalue = 0.0264
The decision region :
Reject the null if :
Pvalue < α
0.0264 > 0.01
Since Pvalue is greater than α ; then, we fail to reject the Null ;
Then there is no significant evidence that the mean graduate age is more Than 31.
B.)
H0: μ ≥ 16
H1: μ < 16
Null Fluid contains 16
Alternative hypothesis, fluid contains less than 16
One sample t - test
C.)
Null hypothesis :
H0 : μ ≤ 12
. The direction of the sign in the alternative hypothesis signifies the type of test or tht opposite direction of the sign in the null hypothesis.
Hence, this is a right tailed test ; Alternative hypothesis, H1 : μ > 12
d.)
If Pvalue is less than or equal to α ; we reject the Null.
Answer:
A sinusoidal model would be used
The kind of function that have consistency in the periodic rate of change is the Average rate of changes
Step-by-step explanation:
The type of model that would be used is sinusoidal model and this is because there is periodic change in the values given ( i.e the rate of changes given )
For percentage rate of changes :
starting from 0.9% there is an increase to 1.3% then a decrease to 1.1% and a further decrease to 1% before an increase to 1.3% and another decrease to 1%
For Average rate of changes:
starting from 2.9 there is a decrease to 2.4, then an increase to 3.7 and another decrease to 3.1 followed by an increase to 3.6 and a decrease back to 3.2
This relation ( sinusoidal model ) is best suited for a linear model because there is a periodic rate of change in the functions
The kind of function that have consistency in the period rate of change is the Average rate of changes
Answer:
Step-by-step explanation:
Slope Formula:
Simply plug in 2 coordinates into the slope formula to find slope <em>m</em>:
Answer:
169.1 unit^2 to the nearest tenth.
Step-by-step explanation:
Area of the parallelogram = base * height
= 24 * 6 unit^2.
Area of the semicircle = 1/2 pi r^2.
Here r = 1/2 * 8 = 4.
So the area is 1/2 * pi * 4^2
= 8pi unit^2.
The area of the whole figure = 24*6 + 8pi
= 169.13 unit^2.