Answer:
[NaCl[ = 0.535M
Explanation:
We determine the moles of solute:
125 g . 1 mol/ 58.45 g = 2.14 moles
Molarity (mol/L) → 2.14 mol / 4L → 0.535M
Molarity is a sort of concentration that indicates the moles of solute in 1L of solution
The second brother Brother because he is much heavier and therefore has more energy to be released hope this helps
<h3>
Answer:</h3>
2.125 g
<h3>
Explanation:</h3>
We have;
- Mass of NaBr sample is 11.97 g
- % composition by mass of Na in the sample is 22.34%
We are required to determine the mass of 9.51 g of a NaBr sample.
- Based on the law of of constant composition, a given sample of a compound will always contain the sample percentage composition of a given element.
In this case,
- A sample of 11.97 g of NaBr contains 22.34% of Na by mass
A sample of 9.51 g of NaBr will also contain 22.345 of Na by mass
% composition of an element by mass = (Mass of element ÷ mass of the compound) × 100
Mass of the element = (% composition of an element × mass of the compound) ÷ 100
Therefore;
Mass of sodium = (22.34% × 9.51 g) ÷ 100
= 2.125 g
Thus, the mass of sodium in 9.51 g of NaBr is 2.125 g
Explanation:
9.0122 g be Maybe, sorry i don't think so
